PHP код:
FormObjectSet fos;
int nextDS;
;
for (nextDS = 1; nextDS <= rhrmOrderTransForm.dataSourceCount(); nextDS++)
{
fos = rhrmOrderTransForm.dataSource(nextDS);
info(strFmt('DataSource name = %1',fos.name()));
info(strFmt('tableId = %1',fos.cursor().tableId));
}